Crazy Link Of The Day: Fibonacci Edition
Let F(n) be the nth Fibonacci number - that is, F(1) = 1, F(2) = 1, F(3) = 2, F(4) = 3, etc.
Then (in pseudo-latex notation)
sum_n F(n) / 10^{n+1} =
0.01 +
0.001 +
0.0002 +
0.00003 +
0.000005 +
0.0000008 +
0.00000013 +
...
is equal to 1/89.
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